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Direction () : Study the following information carefully and answer the given questions. There were some red, some green and some white balls in a bag. Probability of drawing 1 white ball from the bag is 1/3 . If there were 6 more red balls in the bag, the probability of getting 1 green ball would have been1/30 less
If Probability of drawing 1 green ball from the bag is 1/5, then what is the probability of drawing 2 balls such that none of them is red?
3/29
4/29
8/29
8/87
None of these
Let the number of white balls = w, the number of green balls = g and the number of red balls = r, then = w/(w+g+r)=1/3 w+g+r=3w
According to question g/(w+g+r)=1/5 w+g+r=5g Let (w + g + r) = 15x, then w = 5x, g = 3x and r = 15x – 5x – 3x = 7x Also given
So, number of red balls = r = 7x = 14, number of white balls = w = 5x = 10 and number of green balls = g = 3x = 6 Hence, the required probability =
By: Munesh Kumari ProfileResourcesReport error
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