If the average marks of A B C and D in the practical exam is 47 5 and both A and C scored equal mark...........

Quantitative Aptitude (SBI-PO) Case Studies

Direction: Study the given information carefully and answer the following questions.
Four students i.e. A, B, C and D appeared for written and practical examinations of year 2019-20
The information given below is known:
Total Maximum Marks = Maximum marks of written Exam + Maximum marks of practical Exam
Total Maximum weighted score = Maximum marks in written exam × weighted % + Maximum marks in practical exam × weighted %
Weighted score = Marks obtained in written exam × weighted % + Marks obtained in practical exam × weighted %
Weighted percentage of written exam is 60% and that of practical exam is 40%.
Also, maximum marks of written exam is 80 and that of practical exam is 60
It is given that:
Total weighted score of A is 52 . Total weighted score of B is 52 and B obtained 55 marks in practical exam.
C obtained 50 marks in practical exam. Marks obtained by D in written examination is 70 and D obtained 75% marks in practical exam.

If the average marks of A, B, C and D in the practical exam is 47.5 and both A and C scored equal marks in written exam, then what is the average weighted scores of C and D?

None of these

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Explanation:

Let marks obtained by B in written exam = Y
Given, marks obtained by B in practical exam = 55, then
0.6 × Y + 0.4 × 55 = 52
⇒ 0.6Y + 22 = 52
⇒ Y = 50
Marks obtained by D in written exam = 70
Marks obtained by D in practical exam = 75% of 60 = 45
Total weighted score of D = 0.6 × 70 + 0.4 × 45 = 60

Marks scored by A in practical exam = 47.5 × 4 – (55 + 50 + 45)
= 190 – 150 = 40
Let marks scored by A in written exam = x, then
Total weighted score of A = 0.6 × x + 0.4 × 40
⇒ 52 = 0.6x + 16
⇒ 0.6x = 36
⇒ x = 60
Marks scored by C in written exam = Marks scored by A in written exam = x = 60
Total weighted score of C = 0.6 × 60 + 0.4 × 50 = 36 + 20 = 56
So, required average = (56+60)/2= 58
Hence, option 2 is correct.