If D scored 7 1 7 more marks in written exam and C scored 60 marks in written exam then find the dif...........

Quantitative Aptitude (SBI-PO) Case Studies

Direction: Study the given information carefully and answer the following questions.
Four students i.e. A, B, C and D appeared for written and practical examinations of year 2019-20
The information given below is known:
Total Maximum Marks = Maximum marks of written Exam + Maximum marks of practical Exam
Total Maximum weighted score = Maximum marks in written exam × weighted % + Maximum marks in practical exam × weighted %
Weighted score = Marks obtained in written exam × weighted % + Marks obtained in practical exam × weighted %
Weighted percentage of written exam is 60% and that of practical exam is 40%.
Also, maximum marks of written exam is 80 and that of practical exam is 60
It is given that:
Total weighted score of A is 52 . Total weighted score of B is 52 and B obtained 55 marks in practical exam.
C obtained 50 marks in practical exam. Marks obtained by D in written examination is 70 and D obtained 75% marks in practical exam.

If D scored 7(1/7)% more marks in written exam and C scored 60 marks in written exam, then find the difference between obtained weighted score of C and D is what percent of total maximum possible weighted score?

8.56%

9.72%

10.34%

7.52%

None

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Explanation:

Let marks obtained by B in written exam = Y
Given, marks obtained by B in practical exam = 55, then
0.6 × Y + 0.4 × 55 = 52
⇒ 0.6Y + 22 = 52
⇒ Y = 50
Marks obtained by D in written exam = 70
Marks obtained by D in practical exam = 75% of 60 = 45
Total weighted score of D = 0.6 × 70 + 0.4 × 45 = 60

Actual marks scored by D in written exam = 70
New marks scored by D in written exam = 70 + 7(1/7)% of 70 = 75
New total weighted score of D = 0.6 × 75 + 0.4 × 45 = 63
Marks scored by C in written exam = 60
Total weighted score of C = 0.6 × 60 + 0.4 × 50 = 56
Difference between the new weighted score of C and D = 63 – 56 = 7
Total maximum possible weighted score = 60% of 80 + 40% of 60 = 48 + 24 = 72
So, required percentage = 7/72× 100 = 9.72%
Hence, option 2 is correct.