Quantity I A bag contains 50 balls which are green orange and yellow Number of orange balls in the b...........

Quantitative Aptitude (SBI-PO) Arithmatic inequalities

Direction: Each question below contains a statement followed by Quantity I and Quantity II. Find both to find the relationship among them. Mark your answer accordingly.

Quantity I : A bag contains 50 balls which are green, orange and yellow . Number of orange balls in the bag, if probability of picking green ball is 3/5 and and that of either a green or orange ball is 4/5

Quantity II: A bag contains 40 balls green, orange and yellow. The probability of picking orange ball is 3/8 . If the first ball was orange and without replacement, probability of picking a green ball is 4/13 . Number of yellow balls. .

Quantity I > Quantity II

Quantity I < Quantity II

Quantity I ≥ Quantity II

Quantity I ≤ Quantity II

Quantity I = Quantity II or no relation can be established

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Explanation:

For Quantity I:
Probability of picking a green ball = Number of green ball/total balls

3/5= number of green balls/50

=> number of green balls=30

Probability of picking either a green or orange ball = 4/5
Probability of picking either a green or orange ball = either a green or orange ball /total balls

Let number of orange balls be x
So, (x+30)/50=4/5
⇒ x = 10
Quantity I = 10

For Quantity II:
Probability of picking an orange ball = 3/8
Probability of picking orange ball = Number of orange balls / Total balls

3/8=Number of orange balls / 40
Number of orange balls = 15
Now number balls left in the bag = 39
Probability of picking a green ball = 4/13
Probability of picking a green ball = number of green balls/balls left

4/13= number of green balls/39
Number of green balls = 12
Number of orange balls = 15
Number of Yellow balls = Total balls – (Number of green balls + Number of orange balls)
∴ Number of Yellow balls = 40 – (12 + 15) = 13
Quantity II = 13
So, Quantity I < Quantity II.