Explanation:

Quantity I: Total number of balls= 10 + 7 + 13 = 30

Let S be the sample space.

Then, n(S) = number of ways of drawing 5 balls out of 30 =³⁰C₅

Let E1 = event of drawing 2 red balls. n(E1) =¹³C₂

Let E2 = event of drawing 3 balls out of white and blue balls.

Quantity II: Total number of marbles = 8 + 6 + 7 = 21

Let S be the sample space. Then, n(S) = number of ways of drawing 7 marbles out of 21 =²¹C₇

Let E1 = event of drawing 7 marbles in which 4 marbles are brown.

Quantity I > Quantity II

Hence, option (1) is the answer.