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A container contains total 120 liters mixture of milk and water in which quantity of water is 20 liters. If 36 liters mixture taken out from container and 6 liters milk added, then find quantity of water in what percent (approximate) less than that of milk in final mixture?
82%
88%
78%
86%
90%
Ratio of milk to water in mixture = (120 – 20) : 20 = 5 : 1 Total water in final mixture = 20 - 36 × 1 /6 = 14 liters Total milk in final mixture = 100 - 36 × 1/ 6 + 6 = 76 liters Required percentage = (76−14)/ 76 × 100 = 81.67 = 82%
By: Munesh Kumari ProfileResourcesReport error
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