Direction (): - Two quantities that is I and II are given in following questions. Students is expected to solve the quantities and answer them according to given options by comparing their numerical values.

12 men can complete a work in 10 days. 18 women can do the same work in 20 days. 27 children can do that work in 20 days. 9 women and 9 children together do that work for 16 days.
Quantity I: No. of men required to complete the remaining work in one day
Quantity II: 36

Let efficiency of 1 man, 1 woman and 1 child is m, w and c respectively
ATQ,
10 × 12m = 18w × 20 = 27c ×20
2m = 6w = 9c
Let total work = 120 m
Quantity I:
(9w + 9c) × 16 = (3m + 2m) × 16 = 80 m
Remaining work = 120 m – 80 m = 40 m
Number of men required to complete remaining work in one day = 40
Quantity II = 36
Quantity I > Quantity II

By: Munesh Kumari