The sum of the ages of A and B after 10 years would be 106 years If the age of A 6 years before is e...........

Quantitative Aptitude(IBPS RRB CL) Problems based on Ages

The sum of the ages of A and B after 10 years would be 106 years. If the age of A, 6 years before is equal to the age of B, 16 years hence, then what is the present age of A?

32 years

48 years

54 years

62 years

66 years

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Explanation:

Let the present age of A = A years
and present age of B = B years,
then
(A + 10) + (B + 10) = 106
⇒ B = 106 – 10 – 10 – A = 86 – A …. (i)
According to question
A – 6 = B + 16
⇒ B = A – 6 – 16 = A – 22 …. (ii)
From equations (i) and (ii), we get
86 – A = A – 22
⇒ 2A = 86 + 22
⇒ A = = 54.