Explanation:

- Train A starts at 5.00 AM from Mumbai.

- Train B starts at 7.00 AM from Delhi.

- The distance between Mumbai and Delhi is 720 km.

- Train B travels at 60 km/hr.

- Train A can cross a 150 m pole in 5 seconds, which translates to a speed of 30 m/s, or 108 km/hr.

- By the time Train B starts at 7.00 AM, Train A would already have traveled 216 km (2 hours × 108 km/hr).

- The remaining distance for both to cover is 504 km (720 km - 216 km).

- The relative speed combined of Train A and Train B is 168 km/hr (108 km/hr + 60 km/hr).

- Time to meet is 3 hours (504 km ÷ 168 km/hr).

- Therefore, they meet at 10 A.M.

Option:5- 10 A.M is the correct answer.

.