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Two pipes with a leakage are filling a tank. The pipes and the leakage can fill the tank in 18 hrs. But after 3 hrs of working the leakage was observed and repaired. The pipes again started filling the tank and they filled the remaining part in 10 hrs. Find the time taken by the leakage to empty the fully filled tank.
42 hrs
35 hrs
54 hrs
36 hrs
39 hrs
- The pipes and leakage can fill the tank in 18 hours together. This means their combined rate is 1/18 of the tank per hour.
- After 3 hours, they filled 3/18 or 1/6 of the tank, leaving 5/6 to be filled.
- Once the leakage is repaired, the pipes fill the remaining 5/6 of the tank in 10 hours, so the rate of the pipes alone is (5/6) / 10 = 1/12 of the tank per hour.
- The rate of leakage is the difference between the rates with and without leakage: (1/12 - 1/18) = 1/36 of the tank per hour.
- Therefore, the leakage alone would take 36 hours to empty a filled tank.
# Option 4 - 36 hrs
By: Parvesh Mehta ProfileResourcesReport error
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