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A can do a piece of work in 12 days which B can do in 18 days. They begin together but 2 days before the completion of the work, A leaves off. The total number of days to complete the work is?
42/5
7
8
43/5
None of these
Let total work = 36 units ( LCM of 12 and 18)
Efficiency of A =36/12 = 3 units/day
Efficiency of B =36/18 = 2 units/day
1 day work of A and B together = 3 + 2 = 5 units/day
Last 2 days' work of B = 2 x 2 = 4 units
Hence, rest work compelted together = 36 – 4 = 32 units.
Hence, days the rest work is completed by A and B = 32/5days
So, total days = 2 +32/5 = 42/5days
By: Munesh Kumari ProfileResourcesReport error
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