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4 years ago, the ratio of the age of A and B was 5 : 4 and after x years, average of the ages of A and B will be (x + 22) years, then 2 years ago the age of A was
24 years
22 years
(x – 6) years
Cannot be determined
None of these
Let 4 years ago, the ages of A and B be 5a years and 4a years, then Present age of A = (5a + 4) years Present age of B = (4a + 4) years After x years, their average age will be (x + 22) years, then [(5a + 4) + x] + [(4a + 4) + x] = (x + 22) × 2 ⇒ 9a + 8 = 44 ⇒ 9a = 44 – 8 =36 ⇒ a = 36/9 = 4 Hence, 2 years ago the age of A was = (5a + 4) – 2 = 5a + 2 = 5 × 4 + 2 = 22 years
By: Munesh Kumari ProfileResourcesReport error
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