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Two pipes A and B can fill a tank in 24 minutes and 36 minutes. another pipe C can empty the filled tank in 18 minutes. All three pipes A, B and C are alternately open for 1minute each in the empty tank such that pipe A is open first then pipe B and then pipe C. In what time the tank will be filled?
69
67
201
203
198
Let the total capacity = 72 units (LCM of 24, 36 and 18) Efficiency of A =72/24 = 3 Efficiency of B =72/36 = 2 Efficiency of C = –72/18 = –4 Number of units filled in 3 minutes = 3 + 2 – 4 = 1 So, 72 – 5 = 67 unit will be filled in 67 × 3 = 201 minutes Remaining 5 units will be filled in the next 2 minutes Hence, the total time = 201 + 2 = 203 minutes.
By: Munesh Kumari ProfileResourcesReport error
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