A jar contains a mixture of two liquids A and B in the ratio 4 1 When 10 Lt of the mixture was taken...........

Quantitative Aptitude (RBI Grade B) Mixture and Alligation

A jar contains a mixture of two liquids A and B in the ratio 4:1. When 10 Lt. of the mixture was taken out and 10 Lt. of liquid B was poured into the jar, this ratio becomes 2:3. The quantity of liquid A contained in the jar initially was:

10 Lt.

12 Lt.

14 Lt.

18 Lt.

16 Lt.

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Explanation:

Now, 10 Lt. of the mixture was taken out in the same ratio 4:1 . After adding 10 Lt. of mixture ratio of A and B becomes 2:3. As, we are adding B in the mixture the quantity of A will remain same.

Now we have to make A same .

5 = 10Lt. 1 = 2Lt. Final capacity of mixture = 5*2 = 10 Lt. As, 10 Lt. of mixture was removed . ∴Initial Quantity of mixture = 10 + 10 = 20Lt. Initial quantity of A =(4*20)/5 = 16 Lt.