If x., y z arc natural numbers , then the number of diftercnt soluti on s of the equation x + y + z = 6 are :
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Complete-Test, Previous year (2018)
Explanation:
- We need to find how many different sets of natural numbers \((x, y, z)\) can sum up to 6.
- Natural numbers start from 1, so \(x, y, z\) must be at least 1.
- Rewrite the equation as \(x + y + z = 6\), where \(x, y, z > 0\).
- Method: Identify sets where each variable is greater than 0.
- Solution: Try different values for \(x\) and calculate possible corresponding \((y, z)\). Repeat for all possible values.
- The solutions are:
- \( (1,1,4), (1,2,3), (1,3,2), (1,4,1) \)
- \( (2,1,3), (2,2,2), (2,3,1) \)
- \( (3,1,2), (3,2,1) \)
- \( (4,1,1) \)
- Total solutions: 10
Correct Answer: Option: 3, 10
By: Parvesh Mehta ProfileResourcesReport error