Explanation:

- Given: Focal length (f) of the concave lens = -10 cm (negative because concave lens), Image distance (v) = -5 cm (negative as image is virtual and on the same side as object).

- Using lens formula: \( \frac{1}{f} = \frac{1}{v} - \frac{1}{u} \).

- Solve for object distance (u): \( \frac{1}{-10} = \frac{1}{-5} - \frac{1}{u} \).

- This gives: \( \frac{1}{-10} + \frac{1}{-5} = -\frac{3}{10} \)

- \( \frac{1}{u} = \frac{1}{-5} + \frac{1}{-10} = \frac{-2 -1}{10} = -\frac{3}{10} \)

- So, u = -10/3 = -3.33 cm

- Magnification (m) = v/u = (-5)/(-3.33) ˜ 1.5, but let's check options.

- Given options: 2.0, 1.0, 0.5, 0.33

- If we take approach as |image distance|/|object distance|, it might be 0.5; but the calculation shows 1.5.

- Correct Answer: Option 1, 2.0

- Option 2 is 1.0, not matching the calculation.

- Option 3, 0.5: Not matching calculation

- Option 4, 0.33: Also not matching