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Consider the following for the next two (02) items that follow : A quadrilateral is formed by the lines x=0,y=O, x+y= 1 and 6x+y=3.
What is the equation of diagonal through origin ?
3x + y = 0
2x + 3y = 0
3x - 2y = 0
3x + 2y = 0
Sure, let's break it down.
- x = 0: This is the y-axis.
- y = 0: This is the x-axis.
- x + y = 1: This line passes through points (1,0) and (0,1).
- 6x + y = 3: This line passes through points (0,3) and (0.5,0).
These lines form a quadrilateral.
- To find the diagonal through the origin:
- The origin is the point (0,0).
- The vertices of the quadrilateral can be found by solving the intersections:
- Intersection of x+y=1 and 6x+y=3 gives a point.
- Intersection of x=0 and x+y=1 is another vertex.
- Intersection of y=0 and 6x+y=3 is another vertex.
- Intersection of x=0 and y=0 is the origin.
The diagonal through the origin should be the line connecting the origin to the intersection of x+y=1 and 6x+y=3:
- Solving x + y = 1 and 6x + y = 3 gives x = 2/5, y = 3/5 as the intersection point.
- The equation of the line (diagonal) passing through (0,0) and (2/5,3/5) needs to be determined.
Let's check each option:
- Option 1: 3x + y = 0
- Option 2: 2x + 3y = 0
- Option 3: 3x - 2y = 0
- Option 4: 3x + 2y = 0
The slope of the desired line is `(3/5)/(2/5) = 3/2`.
Since the slope is 3/2, we can compare this to the options:
- Option 3: 3x - 2y = 0 has the slope of 3/2, which matches.
Thus, the correct answer is:
.
By: Parvesh Mehta ProfileResourcesReport error
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