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Consider the following for the next two (02) items that follow:
The perimeter of a triangle ABC is 6 times the AM of sine of angles the triangle.
Further BC = √3 and CA = 1.
1 only
2 only
Both 1 and 2
Neither I nor 2
- The perimeter of triangle ABC is given as 6 times the arithmetic mean (AM) of the sines of its angles.
- Let’s denote the angles of the triangle ABC by A, B, and C.
- The AM of the sines of angles = (sin A + sin B + sin C) / 3.
- Perimeter = AB + BC + CA = 6 * [(sin A + sin B + sin C) / 3].
- Given BC = v3 and CA = 1.
- Statement 1: ABC is a right-angled triangle.
- If ABC is right-angled, the sides could follow the Pythagorean theorem.
- Calculating for triangle properties can be consistent with right-angle if sides allow sin(90°) scenario.
- Statement 2: The angles of the triangle are in AP.
- The angles in AP hints at potential arithmetic progression, which may include equal angle differences, consistent with certain triangle types.
- Using calculations aligning the properties, it typically verifies:
- Correct Answer: Option 3 - Both 1 and 2.
- Both statements can often be consistent for such a special triangle set-up.
.
By: Parvesh Mehta ProfileResourcesReport error
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