Define the range of lsquo theta rsquo for the given equation cos theta cos3q cos5q cos7q 0 ........

Mathematics (NDA) Trigonometry

Define the range of ‘θ’ for the given equation {cosθ+ cos3q + cos5q + cos7q =0 }?

θ=(2n₁+1)π/2

θ=(2n₃ +1)π/8 , (2n₁+1)π/2

θ=(2n₃ +1)π/8 , (2n₁+1)π/2 , (2n₂+1)π/4

θ=(2n₂+1)π/4

cosθ+ cos3q + cos5q + cos7q =0

2cos4θ cos3θ +2 cos4θ cosθ =0

cos4θ (cos3θ + cosθ)=0

cos4θ (2cos2θ cosθ)=0

cosθ =0

θ =(2n₁+1)π/2

cos2θ =0

θ=(2n₂+1)π/4

cos4θ =0

θ =(2n₃ +1)π/8

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