Coordinate Geometry

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Find the equation of the normal to the ellipse 9x² + 16y²= 288 at the point (4, 3)?

4x-3y=2

4x-3y=7

4x-y=7

x-3y=7

Explanation:

ellipse 9x² + 16y²= 288

9x² /288+ 16y²/288= 1

x²/32 + y²/18 =1

a²=32 ,b²=18

32x/4 - 18y/3 =14

8x-6y=14

4x-3y=7

By: bhavesh kumar singh

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