Differentiate the following function sin 1 2x 1 x2 with respect to x ........

Explanation:

Put x =tanθ

Θ = tan^-1x

sin^-1 (2x/1+x²) = sin^-1  (2 tanθ  /1  +tan² θ)

= sin^-1 (2 sinθ  cos θ)

= sin^-1(sin 2θ)

=2θ

=2 tan^-1x

Differentiating w. r. to   x

=2 /1+x²