Find maxima and minima of f x 12 x4 3 6x1 3 in 1 1 ........

Explanation:

f(x)=12 x^4/3 -6x^1/3 

f’(x)=12(4/3)x^1/3  -6 (1/3) x^-2/3

f’(x)=16  x^1/3  -  2/x^2/3

 =2(8x  -1)/x^2/3

F’(x)=0

2(8x  -1)/x^2/3   =0

X=1/8

1/8 in[1,-1]

F(1/8 )= -9/4 

F(0)=0

F(1)=18 

f(-1)=6