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Find the arg(1 -i) of the given equation?
( 1-i) = r(cos θ +sin θ ) , then
r cosθ = 1, r sinθ = -1
Thus , r = √2
And cos θ= 1/√2 , sin θ= -1/√2
Therefore , θ = 7π/4
Thus , arg(z) = 7π/4
By: bhavesh kumar singh ProfileResourcesReport error
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