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Find the multiplicative inverse of the given equation (3 +i)2?
8-6i
4/50 -3i/50
4/50 +3i/50
-8-6i
z = ( 3+i)2
= 32 + i2 + 6i
= 8 +6i
Thus , multiplicative inverse is = 1/(8 + 6i) ×(8-6i)/(8-6i)
= ( 8/100 – 6i//100 )
= ( 4/50 - 3i/50 )
By: bhavesh kumar singh ProfileResourcesReport error
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