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Evaluate the arg(-1+i) of the given equation?
Let (-1+i) = r (cosθ + i sin θ)
Then , r cos θ=-1 , r sinθ = 1
Therefore , r= √2
And cos θ= -1/√2 , sin θ= 1/√2
Thus , θ = 3π/4
Therefore , arg(z) = 3π/4
By: bhavesh kumar singh ProfileResourcesReport error
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