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if ‘x’ satisfies the equation |x – 1| + |x – 2| + |x – 3|≥6 then find the value of ‘x’?
x≤-1 or x≥4
x≤1 or x≥4
x≤0 or x≥2
x≤0 or x≥4
Case 1 x≤1 then
1-x+2-x+3-x≥6
x≤0
case2
1 x-1+2-x+3-x≥6 1 Case3 2 x-1+x-2+3-x≥6 x≥6 but 2 Case4 x>3 then x-1+x-2+x-3≥6 x≥4 from case conclusion x≤0 or x≥4
x-1+2-x+3-x≥6
1 Case3 2 x-1+x-2+3-x≥6 x≥6 but 2 Case4 x>3 then x-1+x-2+x-3≥6 x≥4 from case conclusion x≤0 or x≥4
Case3 2 x-1+x-2+3-x≥6 x≥6 but 2 Case4 x>3 then x-1+x-2+x-3≥6 x≥4 from case conclusion x≤0 or x≥4
x-1+x-2+3-x≥6
x≥6
but
2 Case4 x>3 then x-1+x-2+x-3≥6 x≥4 from case conclusion x≤0 or x≥4
Case4 x>3 then
x-1+x-2+x-3≥6
x≥4
from case conclusion x≤0 or x≥4
By: bhavesh kumar singh ProfileResourcesReport error
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