send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
There are 15 students in art class and37 students in dance class and 12 students are enrolled in both activities. When two classes meet at different hours find the number of students, who are either in art class or in dance class.
40
52
45
56
Let A be the set of students in art class and B be the set of students in dance class. n(A) =15, n(B) = 37, n (A ∩ B) = 12 When 2 classes meet at different hours n (A ∪ B) = n(A) + n(B) - n (A ∩ B) = 15 + 37 - 12 = 52 - 12 = 40
By: Munesh Kumari ProfileResourcesReport error
Access to prime resources
New Courses