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Let a die be loaded in such a way that even faces are twice likely to occur as the odd faces. What is the probability that a prime number will show up when the die is tossed?
1 / 3
2 / 3
4 / 9
5 / 9
Prime numbers are 2,3 and 5.
P(prime no.) = P(even no.) P(prime no.) + P(odd no.) P(prime no.) = 2 / 3 × 1 / 3 + 1 / 3 × 2 / 3 = 4 / 9
By: Yachna ProfileResourcesReport error
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