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The position of the point (1, 2) relative to the ellipse 2x2 + 7y2 = 20 is-
outside the ellipse
inside the ellipse but not at the focus
on the ellipse
at the focus
2 x2 + 7 y2 – 20 = 0
Put x = 1, y = 2
2 + 28 – 20 = 10 > 0
∴ (1, 2) lies outside the ellipse.
By: Yachna ProfileResourcesReport error
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