The distance of the point 1 3 from the line 2x nbsp 3y nbsp 6 measured parallel to the line 4x nbsp ......

The distance of the point (1, 3) from the line 2x +3y = 6, measured parallel to the line 4x + y = 4, is -

Required equation of line is: y – 3 = -4 (x – 1) ⇒ 4 x + y = 7

Distance is measured from line 2x+3y=6

Solving these equations, x=3/2 & y = 1

Distance from the point (1, 3) = √ 1/ 4 + 4 = √17 / 2

By: Yachna