The distance of the point 1 3 from the line 2x 3y 6 measured parallel to the line 4x ...........

Mathematics (NDA) Coordinate Geometry

The distance of the point (1, 3) from the line 2x +3y = 6, measured parallel to the line 4x + y = 4, is -

5 / √13 units

3 / √17 units

√17 units

√17 / 2 units

Required equation of line is: y – 3 = -4 (x – 1) ⇒ 4 x + y = 7

Distance is measured from line 2x+3y=6

Solving these equations, x=3/2 & y = 1

Distance from the point (1, 3) = √ 1/ 4 + 4 = √17 / 2

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