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The system of equation kx + y + z = 1, x + ky + z = k and x + y + kz = k2 has no solution if k equals -
k x + y + z = 1, x + k y + z = k and x + y + k z = k2 will have no solution if-
| k 1 1 |
| 1 k 1 | = 0
| 1 1 k |
Solving this determinant, k = 1,-2
If k = 1 then first two equations will become same.
Therefore k= -2
By: Yachna ProfileResourcesReport error
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