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A body has a free fall from a height of 20 m. After falling through a distance of 5 m, then body would
lose one-fourth of its total energy
lose one-fourth of its potential energy
gain one-fourth of its potential energy
gain three-fourth of its total energy
Initial gravitational potential energy of two body U1 = mgh = 20mg [ h = 20m] Initial total energy of the body E = U1 + K 1 = U1 +0 = U1 = 20 mg After falling through 5 m, new potential energy is U2 = mgh' = (20 − 5) = 15mg Loss in potential energy U = U1 − U2 = 20mg −15 mg = 5mg i.e. 1/4 of its potential energy.
By: Munesh Kumari ProfileResourcesReport error
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