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Let [x] denote the greatest integer function. What is the number of solutions of the equation x2 – 4x + [x] = 0 in the interval [0, 2]?
Zero (No solution)
One
Two
Three
x2−4x+[x] = 0 x2–4x=−[x] when x ? [0,1)=>[x]=0 x2–4x=0 x=0,4 0 is in [0,1) so 0 is a solution.
when x [1,2)=>[x]=1 x2–4x=−1 x=(2+√3),(2−√3)
As both solutions are not in [1,2) so both are not solutions.
when x=2=>[x]=2 x2–4x=−2 x=(2+√2),(2–√2) None of these are solutions as we get different value of x.
Result : So equation x2–4x+[x]=0 has only one solution x=0 in [0,2]
By: Munesh Kumari ProfileResourcesReport error
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