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A vessel contains 45 litres of mixture of spirit and water with 20 water content One ninth of the mi...........

Quantitative Aptitude (Phase-1) Mixture and Alligation

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A vessel contains 45 litres of mixture of spirit and water with 20% water content. One ninth of the mixture is withdrawn from the vessel. When x litres of water is added to the remaining mixture, the ratio of spirit and water gets reversed. How much spirit should now be added to it so that the ratio of spirit to water gets restored to its original value? (in litres)

This questions was previously asked in

Nabard grade-A, Previous year Memory Based Paper (2023)

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Explanation:

Let's break down the statements briefly:

- The vessel has 45 litres mixture: 20% water and 80% spirit.

- Water = 9 litres, Spirit = 36 litres.

- One-ninth is withdrawn: 45/9 = 5 litres taken out (contains 1 litre water, 4 litres spirit).

- Left mixture: 40 litres (8 litres water, 32 litres spirit).

- x litres of water added; spirit:water ratio reverses.

- Originally: spirit : water = 32:8 = 4:1. So reversed is 1:4.

- Let water after adding x litres = 8 + x.

- Now: 32/(8 + x) = 1/4 ? 4 × 32 = 8 + x ? 128 = 8 + x ? x = 120 litres.

- New mixture: Spirit = 32, Water = 128.

- To restore original 4:1 ratio: Need S/128 = 4/1 so S = 512.

- Need to add: 512 - 32 = 480 litres of spirit.

Option 5: 480 litres is correct.

Option 5: 480 litres

By: Parvesh Mehta

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