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Two pots contain equal quantity of mixture of Alcohol and water. The ratio of alcohol and water in these pots is 2 : 3 and 4 : 1, respectively. Radha mixed content of the two pots together. Find the ratio of Alcohol and water in new mixture.
4 : 3
2 : 3
3 : 2
3 : 4
None of these
- Pot 1: The ratio of alcohol to water is 2:3.
- This means 2 parts alcohol and 3 parts water.
- Pot 2: The ratio is 4:1.
- Meaning 4 parts alcohol and 1 part water.
- Amount of mixture is equal in both pots.
- To find the new ratio after mixing:
- Total parts for Pot 1 = 2 + 3 = 5 parts
- Total parts for Pot 2 = 4 + 1 = 5 parts
- Alcohol from Pot 1 = \( \frac{2}{5} \)
- Water from Pot 1 = \( \frac{3}{5} \)
- Alcohol from Pot 2 = \( \frac{4}{5} \)
- Water from Pot 2 = \( \frac{1}{5} \)
- New Alcohol Quantity: \( \frac{2}{5} + \frac{4}{5} = \frac{6}{5} \)
- New Water Quantity: \( \frac{3}{5} + \frac{1}{5} = \frac{4}{5} \)
- New Ratio of Alcohol to Water: \( \frac{6}{5} : \frac{4}{5} = 6 : 4 = 3 : 2 \)
- The correct answer is Option 3: 3:2
By: Parvesh Mehta ProfileResourcesReport error
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