send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
This is one of the easy topics but it requires a quick understanding of the terms like, right, left, in the middle of and so on. Also, quick calculations (addition, subtraction, multiplication, etc.) are required to solve numerical series. You can easily score 2-3 marks in this topic by answering these questions attentively.
The series can be of following topics:
Let’s discuss each of them in detail with some suitable examples:
Eg: 723 316 451 539 876
Examples of question format:
Directions: Study the sets of numbers given below and answer the questions based on them.
352 575 669 339 883
Q1. If in each number, the first and the last digits are interchanged, then how many numbers are odd
Ans. d
After interchanging the first and last digits, the new numbers are 253, 575, 966, 933, 388.
Only three numbers are odd which are - 253, 575, 933
Q2. If in each number, all the three digits are arranged in ascending order, which of the following will be the biggest number in the new arrangement?
Ans. A
After rearrangement, the new numbers are - 235, 557, 669, 339, 388.
The biggest number in the new arrangement is 669.
Q3. If each number is multiplied by 3, then what is the sum of the first digits of the largest and the second largest number?
Ans. D
After multiplying each number by 3, we get new numbers as 1056, 1725, 2007, 1017, and 2649. So, the required sum is 2+2=4
So, these were some examples of Numerical Series. Now let's move to next series.
Eg: CUT RAT LIN HUT LAN
Direction: Study the following information carefully and answer the questions given below:
GHB LAS MKT BGO SRV
Q1. If the third alphabet in each of the word is changed to the next alphabet in English alphabetical order, how many words thus formed have more than two different consonants?
Ans. D.
After arranging, the words are GHC LAT MKU BGP SRW GHC, BGP, and SRW have more than two different consonants.
Q2. If in each of the words, all the alphabets are arranged in reverse English alphabetical order within the word, how many words will end with a vowel?
Ans. B
After arranging, the words are HGB SLA TMK OGB VSR Only SLA ends with the vowel.
Q3- How many letters are there in the English alphabetical series between the second letter of the last word from the left and third letter of the fourth word from the right?
Ans. A.
The second letter of the last word from the left is ‘R’. The third letter of the fourth word from the right is ‘S’. So between R and S, there is no letter in English alphabetical series.
Q4.If the given words are arranged in the order as they would appear in the English dictionary from right to left, which of the following will be third from the right?
Ans. B.
After arranging, the SRV MKT LAS GHB BGO, LAS is third from right
Q5.If in each of the given words, each of the consonants is changed to the next letter and each vowel is left unchanged, in how many words thus formed will there be no vowel?
After arranging, the words are HIC MAT NLU CHO TSW. In TSW, there is no vowel.
Now, we will discuss another type of series.
Eg: F 6 H 8 W I 9 Y 4 K 3 L 3 T J E 9 1 0 M 1
Q1. How many such consonants are there in a sequence which are both immediately preceded by and immediately followed by a number?
Ans: d
Letters H, Kand amd M are immediately preceded by or immediately followed by a number.
Q2. After dropping all the numbers, which letter will be second to the left of the fifth letter from the right end?
Ans: c
After dropping all the numbers, second to the left of the fifth letter from the right end or 7th from the right end is Letter Y.
Now, we will discuss next type of series:
Eg: 5 P ) S Y 9 6 # 1 D ? 1 ^ Q % d T % Q ! c 4
Directions: Study the following digit-letter-symbol sequence carefully and answer the questions.
A ? I 4 > 7 C 6 = U K 8 3 # O 5 Z 1 & E 2 < *
Q1- How many symbols are preceded by a digit and succeeded by a vowel?
A ? I 4 > 7 C 6 = U K 8 3 # O 5 Z 1 & E 2 < * , Symbols =, # and & are preceded by a digit and succeeded by a vowel.
Q2. If all the vowels are replaced with their succeeding letters and all the consonants are replaced with their preceding letters. How many letters appear more than once?
Ans. C
The original sequence is A ? I 4 > 7 C 6 = U K 8 3 # O 5 Z 1 & E 2 < * The new sequence after replacement is B ? J 4 > 7 B 6 = V J 8 3 # P 5 Y 1 & F 2 < * So, B and J appear twice.
Q3.If the first 10 elements are interchanged with the last 10 elements and the order of all of them is reversed then which element will be the 9th element from the left?
The original sequence is A ? I 4 > 7 C 6 = U K 8 3 # O 5 Z 1 & E 2 < * The new sequence is * < 2 E & 1 Z 5 O # K 8 3 U = 6 C 7 > 4 I ? A O is 9th from the left.
Q4. If the digits that come after a vowel are increased by 1 and the digits that come after a consonant are decreased by 1. What will be the total sum of the changed digits?
A ? I 4 > 7 C 6 = U K 8 3 # O 5 Z 1 & E 2 < * Digits after vowel are 4, 5 and 2. So, new digits are 5, 6 and 3 Digits after consonant are 6, 8 and 1. So, new digits are 5, 7 and 0 Total Sum = 5+6+3+5+7+0 = 26
So, these were the important types of Series which are asked in the Reasoning section.
Here are some useful tips which you should go through in order to solve the series questions.
By: Manpreet kaur ProfileResourcesReport error
Access to prime resources
New Courses