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At Amit’s Birthday party, there are exactly 57 persons including Amit. They shake hand with each other. Find the total number of handshakes.
1586
1687
1632
1596
1st person shakes hand with 56 persons, 2nd person shakes hand with 55 persons because he already shakes hand with the 1st person. And 3rd person shakes hand with 54 and so on. Therefore, total number of handshakes = 56+55+54+…….+3+2+1 = 1+2+3+…………….+54+55+56 Formula for sum of Natural numbers= n(n+1) / 2 Total number of hand shakes = Sum of 56 natural numbers= 56(56+1) / 2 = 56x57/2 = 1596
By: MIRZA SADDAM HUSSAIN ProfileResourcesReport error
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