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Kunal walks 10 km towards North. From there he walks 6 Km towards South. Then, he walks 3 Km towards east. How far and in which direction is he with reference to his starting point ?
5 Km North
5 Km South
5 Km East
5 Km North-East
Clearly, Kunal moves from A 10 Km northwards upto B, then moves 6 Km southwards upto C, turns towards east and moves 3 km upto D. Then AC = (AB-BC) = 4 Km So Kunal distance from starting point A \begin{aligned} AD = \sqrt{AC^2 + CD^2} \\ = \sqrt{4^2+3^2} \\ = \sqrt{25} = 5 \end{aligned} So AD is 5 Km also with reference to starting point Kunal's direction is North-East.
By: ASRAF UDDIN AHMED ProfileResourcesReport error
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