send mail to support@abhimanu.com mentioning your email id and mobileno registered with us! if details not recieved
Resend Opt after 60 Sec.
By Loging in you agree to Terms of Services and Privacy Policy
Claim your free MCQ
Please specify
Sorry for the inconvenience but we’re performing some maintenance at the moment. Website can be slow during this phase..
Please verify your mobile number
Login not allowed, Please logout from existing browser
Please update your name
Subscribe to Notifications
Stay updated with the latest Current affairs and other important updates regarding video Lectures, Test Schedules, live sessions etc..
Your Free user account at abhipedia has been created.
Remember, success is a journey, not a destination. Stay motivated and keep moving forward!
Refer & Earn
Enquire Now
My Abhipedia Earning
Kindly Login to view your earning
Support
Type your modal answer and submitt for approval
A dinner party is to be fixed for a group of 100 persons. In this party, 50 persons do not prefer fish, 60 prefer chicken and 10 do not prefer both. Find the number of people who prefer both fish and chicken.
20
30
40
10
Let A be the set of persons who prefer Veg and B be the set of persons who prefer Non-veg. Solve by using set theory n(A U B) = 100 - 10 = 90 n(A) = 100 - 50 = 50 and n(B) = 60 Therefore n(A Inter B) = n(A) + n(B) - n(A U B) = 50+60 - 90) = 20
Hence, option 1 is the correct asnwer.
By: Amit Kumar ProfileResourcesReport error
Access to prime resources
New Courses