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If in the above word all the vowels are changed to their next letter while all the consonants are changed to their previous letter then the letters of the word thus formed are to be arranged in alphabetic order from left to right end then how many letters are there in alphabetic series between the letters that are fourth from the left end and third from the right end in newly formed word?
10
13
5
8
The given word = EQUANIMITY After changing all the vowels of the above word to their next letter and all the consonants to their previous letter, we get: FPVBMJLJSX After, arranging the letters of the above word in alphabetic order from left to right end, we get: BFJJLMPSVX Now, the fourth letter from the left end is J and third letter from the right end is S. BFJJLMPSVX And the letters between ‘J’ and ‘S’ in alphabetic series are ‘8’.
By: Amit Kumar ProfileResourcesReport error
Noorbir Singh
3 shall be the answer maam
The question is letters b/t J and S in alphabetic series not it the given word sequence. so ans will be 8
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