Statements T lt H le L lt S le K lt A M F ne S G ge I gt Q U le B...........

Logical Reasoning(Master ) Coded inequality

Statements: T < H ≤ L < S ≤ K < A, M = F ≠ S = G ≥ I > Q, U ≤ B < N = C = I

Conclusions: I. N < A, II. T < B, III. S ≥ N

Neither C2 nor C3 follows

Only C1 and C3 follow

Both C1 and C2 follow

All the conclusions follow

None of the conclusions follow

Statements: T < H ≤ L < S ≤ K < A, M = F ≠ S = G ≥ I > Q, U ≤ B < N = C = I
Conclusions: I. N < A, II. T < B, III. S ≥ N

Combining the equations to find the relationship between N and A, we get

N = C = I ≤ G = S ≤ K < A

Clearly, the common sign of inequalities between N and A is of '<'. Conclusion N < A is hence stays true. C1, hence, follows.

Similarly, combining equations to find the relationship between T and B, we get

T < H ≤ L < S = G ≥ I = C = N > B

Clearly, the signs are getting reversed and hence we can't define a relationship between T and B. C2, hence, doesn't follow.

Similarly, combining equations to find the relationship between S and N, we get

S = G ≥ I = C = N

Here the common sign between S and N is '≥' and the given conclusion is S ≥ N. Evidently , C3 follows.

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