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Logical Reasoning(Master ) Coded inequality

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Statements: M ≥ S , K < A, S = T, A > Y, K > M, Y ≤ O, T ≥ E

Conclusions: M > E, M = E, O > S

Only conclusion I follows

Both conclusions I and III follow

Only conclusion III follows

Either conclusion I or II follows

All the conclusions follow

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Explanation:

Statements: M ≥ S , K < A, S = T, A > Y, K > M, Y ≤ O, T ≥ E
Conclusions: (I) M > E (II) M = E (III) O > S

By combining all the statements, we get the following equation:
O ≥ Y < A > K > M ≥ S = T ≥ E

For conclusion (I): M > E
Here, the common sign between M and E is '≥'. Thus M ≥ E.
Hence conclusion (I) does not follow individually.
For conclusion (II): M = E

Here, the common sign between M and E is '≥'. Thus M ≥ E.
Thus conclusion (II) does not follow individually.
On combining conclusions I and II we get "M ≥ E".
Therefore either conclusion (I) or (II) follows.

For conclusion (III): O > S
Here we can see the opposite signs between O and S, thus no relationship can be established between them.
Therefore conclusion (III) does not follow.