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Logical Reasoning(Master ) Coded inequality

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Statements: A > B = S , E ≥ B > J , H < S ≤ E , A > S ≥ T

Conclusions: E > T, E = T , A > J

None of the conclusions follow

Only conclusion I and either conclusion II or II follow

Either conclusion I or II follows

Only conclusion III and either conclusion I or II follow

All the conclusions follow

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Master Coded inequality

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Explanation:

Statements: A > B = S , E ≥ B > J , H < S ≤ E , A > S ≥ T
Conclusions: E > T, E = T , A > J

For conclusion I: E > T
From statements III and IV, we get:
T ≤ S ≤ E
Here, common sign between T and E is '≤'. Thus T ≤ E or E ≥ T.
Also, From statements I, III and IV, we get:
E ≥ B = S ≥ T
Here, common sign between E and T is '≥'. Thus T ≤ E or E ≥ T.
Hence conclusion I does not follow individually.

For conclusion II: E = T
From statements III and IV, we get:
T ≤ S ≤ E
Here, common sign between T and E is '≤'. Thus T ≤ E or E ≥ T.
Also, From statements I, III and IV, we get:
E ≥ B = S ≥ T
Here, common sign between E and T is '≥'. Thus T ≤ E or E ≥ T.
Hence conclusion II does not follow individually.

For conclusion III: A > J

From statements I and II, we get:
A > B > J
Here, the common sign between A and J is '>'. Thus A > J.
Hence conclusion III follows.
Combining conclusions I and II:
As the final conclusion is E ≥ T, so if we combine both the conclusions I and II i.e. E > T and E = T, we get E ≥ T.
Thus either conclusion I or conclusion II follows.
Therefore, either conclusion I or II and conclusion III follow.