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What is the four-digit number in which the first digit is 1/3 of the second,the third is the sum of the first and second, and the last is three times the second ?
1349
1389
1249
1279
It is given that the first digit is 1/3 of the second. There are 3 such possibilities 1)1 and 3 2)2 and 6 3)3 and 9 Now, the third digit is the sum of the first and second digits. 1)1 + 3 = 4 2)2 + 6 = 8 3)3 + 9 = 12 It is clear that option 3 is not possible. So we are left with only two options. Also, the last digit is three times the second, which rules out the second option. Hence, the answer is 1349.
By: Amit Kumar ProfileResourcesReport error
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