battery of toy C will drain completely ........

Quantitative Aptitude(IBPS PO) Case Studies

Directions : Given data is regarding three automatic toys on two types of movements: Neck movements (NM) and Hand rotation (HR). It starts recording from 9 AM onwards on 12 June. Each toy has different battery percentage and battery capacity.

Toy A: Battery Capacity = 1500 units, Battery Percent = 80%

At every 4th NM and 3rd HR together, 1 unit of battery is consumed. Toy A gets completely discharged at 11 AM.

Toy B: Battery Capacity = 2000 units, Battery percent = 75%

NM = 30/min, HR/min = 50% of NM/min of toy A. At every 3rd NM and 2nd HR together, 1 unit of battery is consumed. Toy C: Battery Capacity = 120% of battery capacity of toy B, Battery Percent = 60%

B, Battery Percent = 60% NM/min = NM/min of toy A + 5, HR = 30/min. at every 3rd NM and 2nd HR together. 1 unit of battery is consumed.

battery of toy C will drain completely?

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11:30 AM

11:45 AM

11:35 AM

11:40 AM

11:50 AM

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Explanation:

- Toy A has 80% of 1500 units, which is 1200 units. Each 4th NM and 3rd HR consume 1 unit. It fully discharges by 11 AM, lasting 2 hours.

- Toy B has 75% of 2000 units, which is 1500 units. It has 15 NM/min and 7.5 HR/min. Every 3rd NM and 2nd HR consume 1 unit.

- Toy C has 120% of Toy B’s capacity, which is 2400 units, and initially 60%, so it has 1440 units. It performs 25 NM/min and 30 HR/min. Each 3rd NM and 2nd HR consume 1 unit.

- Toy C’s battery lasts until 11:40 AM.

Option 4: 11:40 AM is correct.