Explanation:

Let’s break this down. The problem asks: in the number 73951286, how many pairs of digits have exactly the same number of digits between them (in the number) as the numerical difference between those digits? And we need to count both directions (forward and backward).

- Take each pair: for example, 7 and 3 are separated by one digit (difference = 4, but 0 digits between them; not a match).

- You check each pair: count the digits between them, then compare that count to the difference between their values.

- Let me show you the pairs that fit:

Here’s how it pans out:

- 7 and 9: They’re two places apart (7 x x 9...), digit difference is 2. So, 2 digits between, difference is 2. That’s a match.

- 3 and 8: There are five places between them (3 x x x x x 8), digit difference is 5. Match.

- 5 and 2: There are two digits between them (5 x x 2); difference is 3 (no match).

- 9 and 6: Four places between, difference is 3 (no match).

- Take every combination. Only matches are: (7,9) (3,8)

If you repeat for all, you’ll see:

- Only two valid pairs: (7,9) and (3,8)

Now let’s map to the options:

- Option 1: Two

- Option 2: One

- Option 3: Four

- Option 4: Three

- Option 5: More than four

The correct answer is Option 1: Two.

Here’s why:

- There are only 2 pairs fitting the rule.

- It’s easy to overcount if not careful, but really, there aren’t more than four such pairs.

Hope that clears it up!