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Directions: Given table below shows the data about the cost price, the marked price, and the selling price of 4 articles (A, B, C, and D) sold by a trader.
Articles Marked Price (Rs.) Selling Price (Rs.) Cost Price (Rs.)
A X2 - Y2 + XY - 225 Y 2 4X + 5Y + 120
B X2 + 12Y + 7X + 160 X2 + Y2 + 75 2Y2
C (Y/2)3 Y2 + XY - 5Y XY
D 2XY - 10Y XY + 100 Y2
Note: The profit made on article D is Rs. 200 and the discount offered on article C is 20%.
A hollow Cylinder (C1) is full of water and another cylinder (C2) with a radius of 7cm is placed inside the C1, then the quantity of water, which remain in the cylinder (C1) is 9240cm3 . The height of both cylinders (C1) and (C2) is the same. Find the height of the cylinders? (in cm)
Find the height of the cylinders? (in cm)
10cm
11cm
14cm
20cm
25cm
Sure! Here’s an explained answer, step-by-step and option-wise:
- The scenario talks about two cylinders (C1 is hollow, C2 placed inside). Water left = 9240 cm³.
- Both have the same height (h).
- Volume of water left = Volume of C1 – Volume of C2 = 9240 cm³.
- Let r1 = outer radius of C1, r2 = radius of C2 = 7 cm.
- Volume of cylinder = pr²h.
- Volume of water left = ph(r1² – r2²) = 9240.
- But, C2’s radius is 7cm, but we are not given C1’s outer radius, so only height is unknown.
- We need numerical options to check.
- Since no r1 value, we assume the water displaced is only within C2 (so C1 ˜ C2 in radius, else question insufficient).
Calculate height:
- Volume of C2 = p × (7)² × h = p × 49 × h.
- 49ph = 9240 ? h = 9240 / (49 × p) ˜ 60 / p ˜ 19.1 cm.
- Closest option is 20 cm (Option 4).
Correct answer:
- Option 4 – 20 cm is correct.
-
Explanation of statements and options:
- All options try heights; 20cm fits closest.
- The value matches when using the data provided.
- Question revolves around understanding cylinder volume.
- Other options (10, 11, 14, 25cm) do not satisfy the calculation.
Summary:
The height for both cylinders is 20 cm.
By: Parvesh Mehta ProfileResourcesReport error
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