Explanation:

Alright, let’s break this down—here’s what the statements really mean, step by step:

- B’s holiday is on 28th June (a Sunday), and holidays start from here.

- The day before 28th June is a Saturday, so 28th June is definitely the first holiday.

- E is four Sundays after B and is the 11th person overall. E is alone on their holiday.

- A and C share the same date. H, L, and K share another date. G shares only with J.

- D shares with two others but not with J or I.

- No holidays on 12th July, which is a key constraint.

- There must be symmetry in the way Sundays and persons are spread—gaps between groups matter.

Now let’s see who D could share a holiday with:

- D cannot be with F, G, J, I, E, or B, based on clues.

- D shares with two (total three) people—so must be a trio.

- The only trio given is H, L, and K—but none of those trios involve D.

- The other sharing pairs/trios don’t fit, except “A and C have the same holiday”—if D is with A and C, that makes a trio and fits the clues.

Now for the options:

- GJ: Not enough people, D not mentioned with them.

- HK: This is just two, but D must be with a group of three.

- AC: This fits—D, A, and C together.

- K: Single person.

- L: Single person.

So option 3: AC is correct.

Let’s sum up a few core logic points:

- D must be in a group of three.

- D cannot be with J, I, F, E, G, H, K, or L.

- The only duo that can complete a trio with D is A and C.

Bottom line: option 3 is the only one that satisfies all constraints. That’s your answer.