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In the given number ‘85274369’, if all the odd digits are decreased by 1 and all the even digits are decreased by 2, then what would be the sum of the digits which are not repeated in the new number formed after rearrangement?
10
14
2
8
None of these
In the given number ‘85274369’, if all the odd digits are decreased by 1 and all the even digits are decreased by 2,
original number=85274369
after rearrangement=64062248
the sum of the digits which are not repeated in the new number formed after rearrangement=0+8=8
By: Munesh Kumari ProfileResourcesReport error
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