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Direction: Each question contains a statement followed by Quantity I, II and III. Read the information clearly and answer your questions accordingly. The options represent the relations between these three quantities
A) > B) <
C) = D) ≤
Quantity I = 200
Quantity II = 300
Quantity III = 100
Hence, B, A
a) A, B b) B, C
c) B, A d) E, B
e) B, D
Quantity I: Prakhar had an average of 43 in 8 matches. After 9th match his average was 45. His score in 9th match.
Quantity II: The ages of two brothers is in the ratio 3:4. 6 years ago, the ratio of their ages was 7:10. The sum of their present ages in years.
Quantity III: The perimeter of a rectangle is 206 cm and its area is 2520 sq cm. The length of the rectangle in cm.
Suppose his score in 9th match was S.
(43 x 8 + S)/9 = 45
=> 344 + S = 405
S = 61
Suppose their ages are 3n and 4n.
(3n – 6) : (4n – 6) = 7:10
=> n = 9
Sum of present ages = 27 + 36 = 63
Let length and breadth be L & B
L+B = 206/2 = 103 and LB = 2520
=> L, B = 63, 40
The length could be 63 or 40
61 < 63 ≥ 63, 40
Hence, B, E.
By: Munesh Kumari ProfileResourcesReport error
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